Answer:
The answer is below
Explanation:
A) The total bandwidth = 1 Mbps = 1000 Kbps
The requirement for each user = 100 Kbps
Total number of users = Total bandwidth / requirement for each user
Total number of users = 1000 Kbps / 100 Kbps = 10 users
B) Since each user transmits only 10 percent of the time, probability that a given user is transmitting is:
Probability = 0.1
C) Binomial distribution formula is given by:
[tex]P(x)= C(n,x)p^x(1-p)^{n-x}\\\\n = number\ of \ trials,x=number\ of\ success, p=probability\ of\ success \ for\ one\ trial[/tex]Hence:
Probability=[tex](50\ choose\ n)p^n(1-p)^{50-n}[/tex]
[tex]P=C(50,n)p^n(1-p)^{50-n}[/tex]
D) The probability that there are 11 or more is:
[tex]Probability=1-\Sigma\limits^{20}_0 {(50\ choose\ n)p^n(1-p)^{50-n}}[/tex]
