Answer:
[tex]y = 6x + C[/tex]
Step-by-step explanation:
Given the system of equations
dx/dt = 6x − y ............. 1
dy/dt = 36x − 6y ............ 2
Divide equation 2 by 1;
[tex]\dfrac{dy/dt}{dx/dt} = \dfrac{36x-6y}{6x-y} \\\\\dfrac{dy/dt}{dx/dt} = \dfrac{6(6x-y)}{6x-y}\\ \\\dfrac{dy/dt}{dx/dt} = 6\\\\\dfrac{dy}{dt}* \dfrac{dt}{dx} = 6\\\dfrac{dy}{dx} = 6[/tex]
cross multiply
[tex]dy = 6dx\\[/tex]
integrate both sides of the expression
[tex]\int\limits {dy} = \int\limits {6} \, dx \\\\y = 6x + C[/tex]
Hence the general solution to the system of equation is [tex]y = 6x + C[/tex]
