contestada

Find and fix each mistake in the following equilibrium constant expressions.
Part A
2H2S(g)?2H2(g)+S2(g)
Keq=[H2][S2][H2S]
a. Keq=[H2S]^2/[H2]2[S2]
b. Keq=[H2S]/[H2][S2]
c. Keq=[H2]^2[S2]/[H2S]^2
Part B
CO(g)+Cl2(g)?COCl2(g)
Keq=[CO][Cl2][COCl2]
a. Keq=[CO][Cl2]^2/[COCl2]^2
b. Keq=[COCl2]/[CO][Cl2]
c. Keq=[COCl2]^2/[CO][Cl2]^2

Respuesta :

sebassandin

Answer:

A. c. Keq=[H2]^2[S2]/[H2S]^2

B. b. Keq=[COCl2]/[CO][Cl2]

Explanation:

Hello,

In this case, considering the law of mass action which states that the equilibrium expression is written in terms of the concentration of products divided by the concentration of reactants considering the stoichiometric coefficients as powers we obtain:

A. For the reaction:

[tex]2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)[/tex]

The equilibrium expression is:

[tex]Keq=\frac{[H_2]^2[S_2]}{[H_2S]^2}[/tex]

Therefore, answer is c. Keq=[H2]^2[S2]/[H2S]^2.

B. For the reaction:

[tex]CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)[/tex]

The equilibrium expression is:

[tex]Keq=\frac{[COCl_2]}{[CO][Cl_2]}[/tex]

Therefore, answer is b. Keq=[COCl2]/[CO][Cl2].

Regards.

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