Answer:
6957.04N
Explanation:
Using
vf2=vi2+2ad
But vf = 0 .
So convert 50km/hr to m/s, and you need to convert 61 cmto m
(50km/hr)*(1hr/3600s)*(1000m/km) = 13.9m/s
61cm * (1m/100cm) = .61m
So n
0 = (13.9m/s)^2 + 2a(.61m)
a = 158.11m/s^2
So
using F = ma
F = 44kg(158.11m/s^2) = 6957.04N
Answer:
6.95 kN
Explanation:
Given that
Speed of the car, u = 50 kmph
Distance moved by the passenger, s = 61 cm = 0.061 m
Mass of the passenger, m = 44 kg
Converting the initial velocity from km/h to m/s, we have
50 kmph = 50 * 1000/3600
50 kmph = 13.89 m/s
Using one of the equations of motion,
v² = u² + 2as, where v = 0,making a the subject of formula
a = -u²/2s
a = -(13.89²) / 2 * 0.61
a = -192.93 / 1.22
a = -158 m/s²
The force acting on the passenger's leg, F = m.a, so
-F = 44 * -158
F = 6952 N, or 6.95 kN
