Answer:
[tex] \boxed{\sf Acceleration \ (a) = -3.75 \ m/s^2} [/tex]
Given:
Initial velocity (u) = 30 m/s
Final velocity (v) = 15 m/s
Time taken (t) = 4 seconds
To Find:
Acceleration (a) of the car
Explanation:
From equation of motion we have:
[tex] \boxed{ \bold{v = u + at}}[/tex]
By substituting value of v, u & t in the equation we get:
[tex] \sf \implies 15 = 30 + 4a \\ \\ \sf \implies 4a + 30 = 15 \\ \\ \sf \implies 4a = 15 - 30 \\ \\ \sf \implies 4a = - 15 \\ \\ \sf \implies a = - \frac{15}{4} \\ \\ \sf \implies a = - 3.75 \: m {s}^{ - 2} [/tex]
[tex] \therefore[/tex]
Acceleration (a) of the car = -3.75 m/s²
