Answer:
P = 4
Step-by-step explanation:
The LP is:
Maximize p = x+y
x+3y≤4
3x+y≤4
x ≥ 0
y ≥ 0
Solving graphically using the geogebra graphing calculator which is attached, the points are A(0, 4), B(0, 1.33), C(1.33, 0), D(4, 0) and E(1, 1)
The maximum objective is:
For point A(0, 4): Maximize p = x + y = 0 + 4 = 4
For point B(0, 1.33): Maximize p = x + y = 0 + 1.33 = 1.33
For point C(1.33, 0): Maximize p = x + y = 1.33 + 0 = 1.33
For point D(4, 0): Maximize p = x + y = 4 + 0 = 4
For point E(1, 1): Maximize p = x + y = 1 + 1 = 2
Hence, the maximum point is at A(0, 4) which gives P = 4
