Answer:
Explanation:
a ) Distance travelled by them = 3 / 4 x 2π R where R is radius of the circular path .
= .75 x 2 x 3.14 x 2.08
= 9.8 km approx
b )
Displacement = shortest distance between final and initial position
= √2 R
= 1.414 x 2.08
= 2.94 km approx
c ) The direction of displacement is towards north east
so the direction is 45° north of east .
Answer:
(a). The distance is 9.80 km.
(b). The magnitude of the couple’s displacement is 2.94 km.
(c). The direction of the couple’s displacement is 45°.
Explanation:
Given that,
Radius of lake = 2.08 km
(a). We need to calculate the total distance
Using formula of distance
[tex]d=\dfrac{3}{4}(2\pi R)[/tex]
Put the value into the formula
[tex]d=\dfrac{3}{4}(2\pi\times2.08)[/tex]
[tex]d=9.80\ km[/tex]
(b). We need to calculate the magnitude of the couple’s displacement
Using formula of displacement
[tex]D=\sqrt{R^2+R^2}[/tex]
[tex]D=\sqrt{2R^2}[/tex]
[tex]D=\sqrt{2\times(2.08)^2}[/tex]
[tex]D=2.94\ km[/tex]
(c), The direction of the displacement is given by
Using formula of direction
[tex]\tan\theta=\dfrac{R}{R}[/tex]
[tex]\theta=\tan^{-1}(1)[/tex]
[tex]\theta=45^{\circ}[/tex]
Hence, (a). The distance is 9.80 km.
(b). The magnitude of the couple’s displacement is 2.94 km.
(c). The direction of the couple’s displacement is 45° relative to the east.
