Respuesta :
Answer:
The molar heat capacity at constant volume is 21.62 JK⁻¹mol⁻¹
The molar heat capacity at constant pressure is 29.93 JK⁻¹mol⁻¹
Explanation:
We can calculate the molar heat capacity at constant pressure from
[tex]C_{p,m} = \frac{C_{p} }{n}[/tex]
Where [tex]C_{p,m}[/tex] is the molar heat capacity at constant pressure
[tex]{C_{p} }[/tex] is the heat capacity at constant pressure
and [tex]n[/tex] is the number of moles
Also [tex]{C_{p} }[/tex] is given by
[tex]{C_{p} } = \frac{\Delta H}{\Delta T}[/tex]
Hence,
[tex]C_{p,m} = \frac{C_{p} }{n}[/tex] becomes
[tex]C_{p,m} = \frac{\Delta H }{n \Delta T}[/tex]
From the question,
[tex]\Delta H[/tex] = 229.0 J
[tex]n[/tex] = 3.00 mol
[tex]\Delta T[/tex] = 2.55 K
Hence,
[tex]C_{p,m} = \frac{\Delta H }{n \Delta T}[/tex] becomes
[tex]C_{p,m} = \frac{229.0}{(3.00) (2.55)}[/tex]
[tex]C_{p,m} =[/tex] 29.93 JK⁻¹mol⁻¹
This is the molar heat capacity at constant pressure
For, the molar heat capacity at constant volume,
From the formula
[tex]C_{p,m} = C_{v,m} + R[/tex]
Where [tex]C_{v,m}[/tex] is the molar heat capacity at constant volume
and [tex]R[/tex] is the gas constant ([tex]R[/tex] = 8.314 JK⁻¹mol⁻¹)
Then,
[tex]C_{v,m} = C_{p,m} - R[/tex]
[tex]C_{v,m} = 29.93 - 8.314[/tex]
[tex]C_{v,m} =[/tex] 21.62 JK⁻¹mol⁻¹
This is the molar heat capacity at constant volume
