Answer:
[tex]\rho =2.6g/mL[/tex]
Explanation:
Hello,
In this case, considering that the density is defined as:
[tex]\rho =\frac{m}{V}[/tex]
Thus, since 1 kg equals 1000 g and 1 L equal 1000 mL, the required density in g/mL turns out:
[tex]\rho =\frac{1.7132kg}{0.65L}*\frac{1000g}{1kg}*\frac{1L}{1000mL} \\\\\rho=2.6g/mL[/tex]
Take into account that since 0.65 L has two significant figures, the result is also shown with two significant figures.
Regards.
