Answer:
The time taken for the ball to return to the starting point is is 7.4 s
Explanation:
Given;
initial velocity of the ball, u = 36 m/s
the final vellocity at maximum height, v = 0
let time taken for the ball to reach maxmimum height = t
Time taken for the ball to return to the starting point is known as time of flight, calculated as;
[tex]t = \frac{v-u}{-g} \\\\T = 2t\\\\T = \frac{2(0-u)}{-g}\\\\T = \frac{-2u}{-g}\\\\ T = \frac{2u}{g}[/tex]
T = (2 x 36) / 9.8
T = 7.4 s
Therefore, the time taken for the ball to return to the starting point is is 7.4 s
