Answer:
The hot resistance of a light bulb is 205.714 ohms.
Explanation:
Hot resistance can be found by using Ohm's Law and definition of power, whose expression as a function of power and voltage is:
[tex]R = \frac{V^{2}}{\dot W}[/tex]
Where:
[tex]\dot W[/tex] - Power, measured in Watts.
[tex]V[/tex] - Voltage, measured in Volts.
[tex]R[/tex] - Resistance, measured in Ohms.
Given that [tex]V = 120\,V[/tex] and [tex]\dot W = 70\,W[/tex], we find that hot resistance is:
[tex]R = \frac{(120\,V)^{2}}{70\,W}[/tex]
[tex]R = 205.714\,\Omega[/tex]
The hot resistance of a light bulb is 205.714 ohms.
