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A time standard was set as 0.20 hour per unit based on the 20th unit produced. Assume the task has a 60 percent learning curve. Refer to Exhibit 6.4. What would be the expected time of the 40th, 80th, and 160th units? (Do not round intermediate calculations. Round your answers to 2 decimal places.)

Respuesta :

Answer:

40th unit = 0.11 hr

80th unit = 0.06 hr

160th unit = 0.03 hr

Explanation:

Given :

[tex]$T_{20} = 0.2$[/tex]

Learning rate = 60% = 0.6 (r)

Now using the learning curve equation,

[tex]$ T_n = T_1(n)^b$[/tex]

where b is  [tex]$b= \frac{\ln r}{\ln 2} = \frac{\ln 0.6}{\ln 2} $[/tex]  = -0.833

Now

[tex]$ T_{20} = T_1(20)^{-0.833}$[/tex]

[tex]$ 0.20 = T_1 (0.0824)$[/tex]

[tex]$T_1$[/tex] = 2.5

For 40th unit

[tex]$ T_{40} = 2.5(40)^{-0.833}$[/tex]

      = 0.11 hrs

For 80th unit

[tex]$ T_{80} = 2.5(80)^{-0.833}$[/tex]

      = 0.06 hrs

For 160th unit

[tex]$ T_{160} = 2.5(160)^{-0.833}$[/tex]

        = 0.03 hr

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