Answer:
145 kernels
Step-by-step explanation:
The dimensions of the box are L= 5cm W=2.5cm H= 2.5.
Size of a kernal is 0.6 cm
We need to find number of kernels that could fit inside of the box. Let n be such kernals. So,
[tex]n=\dfrac{\text{volume of box}}{\text{volume of one kernel}}[/tex]
Kernal is in the shape of cube
So,
[tex]n=\dfrac{\text{volume of cuboid}}{\text{volume of one cube}}\\\\n=\dfrac{LWH}{a^3}\\\\n=\dfrac{5\times 2.5\times 2.5}{(0.6)^3}\\\\n=144.67\\\\\text{or}\\\\n=145\ \text{kernels}[/tex]
Hence, 145 kernels could fit inside of the box.