On a beautiful day you decide to go fishing with your younger brother Ben. Ben has not been fishing before so he doesn't know how to properly cast out his line. He puts the lure 24.5 cm above the water before letting it drop straight down. The line accelerates until it hits the water then continues to the bottom of the lake at a constant speed. It takes the lure 5.00 s to reach the bottom of the lake from when it was released by Ben.

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Answer:

The question is not complete, below is the complete question:

On a beautiful day you decide to go fishing with your younger brother Ben. Ben has not been fishing before so he doesn't know how to properly cast out his line. He puts the lure 24.5 cm above the water before letting it drop straight down. The line accelerates until it hits the water then continues to the bottom of the lake at a constant speed. It takes the lure 5.00 s to reach the bottom of the lake from when it was released by Ben. How deep is the lake? (Assume the lure accelerates at the free fall rate of 9.8 m/s² until it hits the water.)

Answer:

depth of lake = 98cm

Explanation:

Total height of free fall = distance above water + depth of lake = h

for an object falling under the influence of gravity

[tex]h = \frac{1}{2} gt^2\\where:\\h = height\\g = acceleration\ due\ to\ gravity = 9.8\ m/s^2\\t = time = 5 s\\\therefore h = \frac{1}{2} \times 9.8 \times 5^2\\h = 0.5 \times 9.8 \times 25\\h = 122.5cm[/tex]

Total distance travelled = 122.5cm

Total distance travelled = height above water + depth of lake

122.5 = 24.5 + depth of lake

depth of lake = 122.5 - 24.5

depth of lake = 98cm