Answer:
The sum is -1/2
Step-by-step explanation:
Your question is not too clear to me but if I reframe it, it will turn to this;
Find the sum of In{1 - (1/n^2)} for n >= 2
£n>=2 = In{1 - (1/2^2)} + In{1 - (1/3^2)} + In{1 - (1/4^2)} + ......
£n>=2 = In{1 - (1/4)} + In{1 - (1/9)} + In{1 - (1/16)}
£n>=2 = In(3/4) + In(8/9) + In(15/16)
£n>=2 = -0.287 + -0.117 + -.064 = −0.468
£n>=2 = -0.5 by approximation
£n>=2 = -1/2 is the sum and by evaluation it converge.
