Answer:
The average speed of a neon atom is 414.04 m/s
Explanation:
Given;
energy of the neon gas, E = 1200 J
mass of the neon gas, m = 14 g = 0.014 kg
The speed of the neon atom is given by Maxwell-Boltzmann;
E = ¹/₂mv²
where;
v is the average speed of the neon atom
1200 = ¹/₂(0.014)v²
2 x 1200 = 0.014v²
2400 = 0.014v²
v² = 2400 / 0.014
v² = 171428.57
v = √ 171428.57
v = 414.04 m/s
Therefore, the average speed of a neon atom is 414.04 m/s
The average speed of a neon atom will be 414.04 m/s.
The total distance traveled by an object divided by the total time taken is the average speed.
The average speed of an object indicates the pace at which it will traverse a distance. The metric unit of speed is the meter per second.
The given data in the problem is;
E is the energy of the neon gas, = 1200 J
m is the mass of the neon gas= 14 g = 0.014 kg
v is the speed of the neon atom=?
From the Maxwell-Boltzmann equation;
[tex]\rm E= \frac{1}{2} mv^2 \\\\ v=\sqrt{\frac{2E}{m} } \\\\ v=\sqrt{\frac{2 \times 1200 }{0.014} } \\\\ v= 414.04 \ m/s[/tex]
Hence the average speed of a neon atom will be 414.04 m/s.
To learn more about the average speed refer to the link;
https://brainly.com/question/12322912
