Answer:
1). Displacement = 24 m
2). Distance = 28 m
Explanation:
We will use the concept that distance is a scalar quantity and displacement is a vector quantity.
1). Displacement of the car between 0 s and 24 s
Displacement = distance between origin (0, 0) and a point on x - axis (24, 0)
= 24 - 0
= 24 meters
2). Distance traveled by the car = Distance traveled by the car on the ramp
= Distance traveled on the tracks (AB + BC + CD)
AB = [tex]\sqrt{6^2+8^2}[/tex]
= [tex]\sqrt{36+64}[/tex]
= [tex]\sqrt{100}[/tex]
= 10 m
BC = 16 - 8
= 8 m
CD = [tex]\sqrt{8^2+6^2}[/tex]
= 10 m
Therefore, distance traveled by the car = 10 + 8 + 10
= 28 m
