An object thrown in the air has a velocity after t seconds that can be described by v(t) = -9.8t + 24 (in meters/second) and a height h(t) = -4.9t 2 + 24t + 60 (in meters). The object has mass m = 2 kilograms. The kinetic energy of the object is given by K = __1 2mv2 , and the potential energy is given by U = 9.8mh. Find an expression for the total kinetic and potential energy K + U as a function of time. What does this expression tell you about the energy of the falling object?

Respuesta :

Answer and Explanation: Kinetic energy is related to movement: it is the energy an object possesses during the movement. it is calculated as:

[tex]K=\frac{1}{2}mv^{2}[/tex]

For the object thrown in the air:

[tex]K=\frac{1}{2}.2.[v(t)]^{2}[/tex]

[tex]K=(-9.8t+24)^{2}[/tex]

[tex]K=96.04t^{2}-470.4t+576[/tex]

Kinetic energy of the object as a function of time: [tex]K=96.04t^{2}-470.4t+576[/tex]

Potential energy is the energy an object possesses due to its position in relation to other objects. It is calculated as:

[tex]U=mgh[/tex]

For the object thrown in the air:

[tex]U=9.8.2.h(t)[/tex]

[tex]U=9.8.2.(-4.9t^{2}+24t+60)[/tex]

[tex]U=-96.04t^{2}+470.4t+1176[/tex]

Potential energy as function of time: [tex]U=-96.04t^{2}+470.4t+1176[/tex]

Total kinetic and potential energy, also known as mechanical energy is

TME = [tex]96.04t^{2}-470.4t+576[/tex] + ([tex]-96.04t^{2}+470.4t+1176[/tex])

TME = 1752

The expression shows that total energy of an object thrown in the air is constant and independent of time.