Answer:
Step-by-step explanation:
Given the vector v = 6i-6j, the magnitude is expressed as shown;
|v| = √6²+(-6)²
|v| = √36+36
|v| = √72
|v| = √2×36
|v| = √36×√2
|v| = 6√2
The modulus of the vector is 6√2
To get the direction, we will use the formula;
(theta) = tan^-1(y/x)
(theta) = tan^-1(-6/6)
(theta) = tan^-1(-1)
(theta) = -45°
Since the angle is negative and tan theta is negative the in the second quadrant, the positive direction angle of the vector will be 180° - 45° = 135°
