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Consider the definition in OCaml
let fabcd = a.(if b then c else d)
Which of the following must hold (zero, one or more answers can be correct)?
A. The type of a is int array.
B. The type of b is bool.
C. The type of c is int.
D. The type of d is int.
E. The return type of f is int.

Respuesta :

batolisis

Answer:

The type of b is bool ( B )

The type of c is int ( C )

The type of d is int ( D )

Explanation:

The options that must hold zero are: The type of b is bool,The type of d is int and The type of c is int.

If b is true then c or d is true because c and d are int. this is because b been a true/false means that d and c are boolean int. because d and c are assigned to integers  

MrRoyal

The statements that must hold are:

  • b. The type of b is bool
  • c. The type of c is int
  • d. The type of d is int

The definition is given as:

let fabcd = a.(if b then c else d)

From the above definition, we have the following if condition

if b then c else d

This means that:

Variable b can only take either true or false, as its value.

So, b is of Boolean type

Variables c and d can take any numerical data type such as int, floats, and any character type such as char and string.

This means that:

Options (c) and (d) can also hold.

Hence, the true options are: (b), (c) and (d)

Read more about program definition at:

https://brainly.com/question/25665378

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