20-ohm resistor is connected to a 10 V battery. The battery is then replaced by a battery that provides a larger voltage what happens to the current through the resistor

Respuesta :

Explanation:

It is given that,

Resistance, R = 20 ohms

Voltage of the battery, V = 10 V

We can find current flowing through the circuit using Ohm's law as follows :

V = IR

[tex]I=\dfrac{V}{R}\\\\I=\dfrac{10}{20}\\\\I=0.5\ A[/tex]

It can be seen from the Ohm's law, that the current is directly proportional to the voltage. It means that if the battery is replaced by a battery that provides a larger voltage, the current through the circuit will be more than 0.5 A i.e. it increases.

The current via the circuit will be more than 0.5 A i.e. it increases.

Ohm law:

Since

Resistance, R = 20 ohms

The voltage of the battery, V = 10 V

Now we applied the above law i.e.

V = IR

I = V/R

I = 10/20

I = 0.5 A

Based on the above calculations, we can say that the current should be directly proportional to the voltage. That means in the case when the battery should be replaced by the battery that gives the larger voltage so the current should be more than 0.5 A due to this it increased.

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