Given :
Electronic configuration of an electron :
[tex]1s^2\ 2s^2\ 2p_x^2\ 2p_y^2\ 2p_z^2\ 3s^2 \ 3p_x^2\ 3p_y^2\ 3p_z^2[/tex] .
To Find :
The element having such an electronic configuration .
Solution :
We know , the sum of all the power of s and p in all the orbit gives total number of atoms in elements .
So , atomic number is :
[tex]Z=2+2+(2+2+2)+2+(2+2+2)\\\\Z=18[/tex]
Since , the atomic number is 18 .
Therefore , the element is Argon .
Hence , this is the required solution .
