Please help with this simultaneous equation you can use any method(Only number 6)

Answer:
Pencil: $0.60 Rubber: $0.48
Step-by-step explanation:
Let the cost of a pencil be p and the cost of a rubber be r.
[tex]p+r=1.08[/tex] (Equation 1)
[tex]4p=5r[/tex] (Equation 2)
Divide both sides by 4:
[tex]p=\frac{5}{4} r[/tex]
Substitute this into Equation 1:
[tex]\frac{5}{4} r+r=1.08[/tex]
Multiply both sides by 4:
[tex]\frac{5}{4}r* \:4+r* \:4=1.08*4[/tex]
[tex]5r+4r=4.32[/tex]
[tex]9r=4.32[/tex]
Divide both sides by 9:
[tex]\frac{9r}{9}=\frac{4.32}{9}[/tex]
[tex]r=0.48[/tex]
Since r + p = 1.08,
[tex]p=1.08=0.48=0.60[/tex]