Given :
Mass of [tex]H_2SO_4[/tex] is 571.6 g per liter .
Density of solution , [tex]\rho=1.329\ g/cm^3[/tex] .
To Find :
a. Mass percentage
b. Mole fraction
c. Molality
d. molarity of H2SO4 in this solution.
Solution :
Molar mass of [tex]H_2SO_4[/tex] , m = 1329 g/mol .
a ) Mass of [tex]H_2SO_4[/tex] contain in 1 liter is 1329 g .
[tex]mass \ \%=\dfrac{571.6}{1329}\times 100=43.01 \%[/tex]
b ) Moles of [tex]H_2SO_4[/tex] = [tex]\dfrac{571.6\ g}{98\g/mol}=5.83\ mol[/tex] .
Moles of [tex]H_2O[/tex] = [tex]\dfrac{1329-571.6\ g}{18\ g/mol}=42.08\ mol[/tex] .
Mole fraction [tex]=\dfrac{5.83}{5.83+42.08}=0.12[/tex] .
c ) Molarity of [tex]H_2SO_4[/tex] [tex]=\dfrac{5.83\ mol}{1 \ L}=5.83\ M[/tex] .
Hence , this is the required solution .
