what is the slope of the line below -3,2 3,2
a. negative
b.undefined
c. positive
d.zero

Answer:
0
Step-by-step explanation:
let (-3,2) be (x1,y1)
and(3,2)be(x2,y2)
Now,
slope = y2-y1/x2-x1
=2-2/3-(-3)
=0/3+3
=0/6
therefore slope=0