A car moves with constant velocity along a straight road. Its position is x1 = 0 m at t1 = 0 s and is x2 = 66 m at t2 = 6.0 s . Answer the following by considering ratios, without computing the car's velocity.(Express your answer to two significant figures and include the appropriate units.) 1.What is the car's position at t = 3.0 s ? 2.What will be its position at t = 24 s ?
Explanation: 66m= 6s so, to find the position at 3s you just need to take 66/2 = 33m cause 3 is half of 6. & for 2 you will take 66x4= 264m cause it took 4s multiply by the original 6s to get 24s. Answer: 1 is 33m and 2 is 264m