Answer:
9x+8
Step-by-step explanation:
Given DS = 3x+10 and SE = 6x-2_ the value of DE is expressed as shown;
DE = DS+SE
Substitute the given functions into the formula to get DE
DE = (3x+10)+(6x-2)
Open the parentheses
DE = 3x+10+6x-2
Collect the like terms
DE = 3x+6x+10-2
DE = 9x+8
Hence the value of DE is 9x+8
