Respuesta :
Answer:
1/9
Step-by-step explanation:
The applicable rule of exponents is ...
a^0 = 1 . . . . a ≠ 0
__
[tex]\dfrac{(-3)^0}{(-3)^2}=\dfrac{1}{(-3)(-3)}=\boxed{\dfrac{1}{9}}[/tex]
Answer:
1/9
Step-by-step explanation:
The applicable rule of exponents is ...
a^0 = 1 . . . . a ≠ 0
__
[tex]\dfrac{(-3)^0}{(-3)^2}=\dfrac{1}{(-3)(-3)}=\boxed{\dfrac{1}{9}}[/tex]