Answer:
[tex] \boxed{\sf Specific \ heat \ of \ the \ substance \ (c) = 0.85 \: J/g \degree C } [/tex]
Given:
Mass (m) = 10.0 g
Rise in temperature (∆T) = 8.58°C
Energy required (Q) = 73.2 J
To Find:
Specific heat of the substance (c)
Explanation:
Specific heat (c) of a substance is the energy required to raise the temperature of one gram of the substance by one degree Celsius.
Formula of specific heat is given as:
[tex] \boxed{ \bold{c = \frac{Q}{m\Delta T}}}[/tex]
By substituting value of Q, m & ∆T in the formula we get:
[tex] \sf \implies c = \frac{73.2}{10 \times 8.58} \\ \\ \sf \implies c = \frac{73.2}{85.8} \\ \\ \sf \implies c = 0.85 \: J/g \degree C [/tex]
