Answer:
Positive where x < -6 and x > 8.
Step-by-step explanation:
y = x^2 - 2x - 48
The graph of this is a parabola which opens upwards ( because the coefficient of x^2 ( = 1) is positive). So it will positive to the left and to the right of the points where it passes through the x axis ( i e the zeros of the function).
x^2 - 2x - 48 =0
(x + 6)(x - 8) = 0
So the zeros are at x = (-6,0) and at (8, 0).
Therefore the intervals are x < -6 and x > 8.
