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What is 90.125 written in expanded form? A. 9 × 10 + 1 × 1 + 2 × 1 10 + 5 × 1 100 B. 9 × 1 + 1 × 1 10 + 2 × 1 100 + 5 × 1 1 , 000 C. 9 × 10 + 1 × 1 10 + 2 × 1 100 + 5 × 1 1 , 000 D. 9 × 1 + 1 × 1 100 + 2 × 1 1 , 000 + 5 × 1 10 , 000

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Answer:

b or d I think pretty sure that's right

Using digit concepts, it is found that, in expanded form:

[tex]90.125 = 9 \times 10^1 + 0 \times 10^0 + 1 \times 10^{-1} + 2 \times 10^{-2} + 5 \times 10^{-3}[/tex]

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  • Each number can be divided into an integer part and a decimal part. For 90.125, the integer part is 90 and the decimal part is 0.125.
  • In the integer part, starting from the last digit, each is multiplied by the "next" power of 10, thus:

[tex]90 = 0 \times 10^{0} + 9 \times 10^{1} = 9 \times 10^{1} + 0 \times 10^{0}[/tex]

  • For the decimal part, starting from the first decimal digit, the same logic applies, using negative powers of 10 starting at -1, thus:

[tex].125 = 1 \times 10^{-1} + 2 \times 10^{-2} + 5 \times 10^{-3}[/tex]

Combining the integer and decimal parts, we get that the number in expanded form is:

[tex]90.125 = 9 \times 10^1 + 0 \times 10^0 + 1 \times 10^{-1} + 2 \times 10^{-2} + 5 \times 10^{-3}[/tex]

A similar problem is given at https://brainly.com/question/17574571

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