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PLEASE HELP!!!! Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discriminant has no real solution, and a quadratic equation with a discriminant of zero has one real solution.

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Hey there! I'm happy to help!

In the quadratic formula, the discriminant is square rooted. In this formula you have a ± before this radical. If the discriminant is positive, the solution can be either subtracting or adding the number, so there are 2 real solutions.

If it is 0, subtracting or adding are the same, so there will be just one solution.

You cannot have a negative square root. It is impossible with real numbers, so there are no real solutions.

I hope that this helps! Have a wonderful day! :D

Answer:

B (–4, –12)

Step-by-step explanation:

If its even the right question