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Bryan Allen pedaled a human-powered aircraft across the English channel from the cliffs of Dover to Cap Gris-Nez on June 12, 1979. He flew for 169 minutes at an average velocity of 3.53 m/s in a direction 45.0∘ degrees south of east. Allen encountered a headwind averaging 2.00 m/s almost precisely in the opposite direction of his motion relative to the earth. What was his average velocity relative to the air?

Respuesta :

Answer:

The answer is "[tex]5.53 \ \frac{m}{s}[/tex]"

Explanation:

apply the formula for calculating the average velocity to the relative air

[tex]V_{PG} =V_{PA}+V_{AG}[/tex]

[tex]\Rightarrow V_{PA} = V_{PG} -V_{AG}[/tex]

Given value:

[tex]V_{AG} = -2 \ \frac{m}{s}[/tex]

[tex]V_{PG} =3.53[/tex]

[tex]\Rightarrow V_{PA} = 3.53 - (-2) \\\\\Rightarrow V_{PA} = 3.53 +2 \\\\\Rightarrow V_{PA} = 5.53 \\\\[/tex]

The final answer is "[tex]5.53 \ \frac{m}{s}[/tex]" in the south-east direction.

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