Answer:
f = 96.56 Hz
Explanation:
A soda bottle can be simulated by a system of a tube with one end open and the other closed. In this case at the closed end we have a node and at the open end a maximum, so the wavelength is
λ = 4L / n
where n = 1, 3, 5, ...
for our case the speed of sound is
v = λ f
we substitute
f / v = 4L / n
calculate
290 / (340 4) = L / n
0.213 = L / n
In the exercise the value of n is not indicated, but we can assume that it is the fundamental answer, therefore n = 1
L = 0.213 m
now we can calculate the frequency of the following resonance n = 3
f = 4L v / n
f = 4 0.213 340/3
f = 96.56 Hz
