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What is wrong with the equation? π 4 sec(θ) tan(θ) dθ = 4 sec(θ) π π/3 = −12 π/3 There is nothing wrong with the equation. f(θ) = 4 sec(θ) tan(θ) is not continuous on the interval [π/3, π] so FTC2 cannot be applied. f(θ) = 4 tan(θ) is not continuous on the interval [π/3, π] so FTC2 cannot be applied. f(θ) = 4 sec(θ) is not continuous at θ = π/3 so FTC2 cannot be applied. The lower limit is not equal to 0, so FTC2 cannot be applied.

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Answer:

if f(θ) = 4 is true then print"hello" elif print "ues'

The given equation is not defined in the interval [tex]\left[\dfrac{\pi}{3},\pi\right][/tex]. Therefore, FTC2 is not applied and this can be determined by using the property of the trigonometric function.

Given :

Equation  --  [tex]\rm \int^{\pi}_{\pi/3}7\;sec\theta\; tan\theta \;d\theta[/tex]

The following steps can be used in order to determine what is wrong with the given equation:

Step 1 - Write the given equation.

[tex]\rm \int^{\pi}_{\pi/3}7\;sec\theta\; tan\theta \;d\theta[/tex]

Step 2 - In the given equation [tex]\rm sec\theta[/tex] is not defined at [tex]\theta = \pi/2[/tex].

Step 3 - In the given equation [tex]\rm tan\theta[/tex] is not defined at [tex]\theta = \pi/2[/tex].

Step 4 - From the above steps, it can be concluded that the given equation is not defined in the interval [tex]\left[\dfrac{\pi}{3},\pi\right][/tex]. Therefore, FTC2 is not applied.

For more information, refer to the link given below:

https://brainly.com/question/13710437

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