Answer:
[tex]4.92x10^{23}molecules H_2O[/tex]
Explanation:
Hello,
In this case, since the chromium(III) oxalate trihydrate is Cr₂(C₂O₄)₃ ·3H₂O whose molar mass is 422 g/mol and one mole of chromium(III) oxalate trihydrate contains three moles of water, by also considering that one mole of substance contains the Avogadro´s number in particles, the number of water molecules turns out:
[tex]=115gCr_2(C_2O_4)_3\ 3H_2O*\frac{1molCr_2(C_2O_4)_3\ 3H_2O}{422gCr_2(C_2O_4)_3\ 3H_2O}*\frac{3molH_2O}{1molCr_2(C_2O_4)_3\ 3H_2O} *\frac{6.022x10^{23}molecules H_2O}{1molH_2O} \\\\=4.92x10^{23}molecules H_2O[/tex]
Best regards.
