Respuesta :
Answer:
0.2
Step-by-step explanation:
Missing table in the question
- Orange - 51
- Grape - 30
- Cherry - 69
Solution
Total number of juice bought:
- 51 + 30 + 69 = 150
Probability of a student choosing grape flavor:
- Probability = favorable outcomes / total outcomes
- P(grape) = 30/150 = 1/5 = 0.2
Answer is 0.2
Probability that a student who bought juice chosen at random purchased the grape flavor is 0.2.
According to the question, there are three lunch periods and the number of students that take different flavors of juice is shown below;
- Orange - 51
- Grape - 30
- Cherry - 69
Since probability = Expected outcome/sample space
Sample space = 51 + 30 + 69 = 150
Probability that a student who bought juice chosen at random purchased the grape flavor = 30/150 = 0.2
Learn more: https://brainly.com/question/12108425
Missing parts;
Three flavors of juice are offered at a school cafeteria. The table shows the number of students who purchased each flavor during three lunch periods. Orange Grape Cherry 51 30 69 Based on the table, what is the probability that a student who bought juice chosen at random purchased the grape flavor? O A. 0.2 O B. 0.25 O C. 0.3 D. 0.33