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Hey there! I'm happy to help!
Angles A and B are alternate exterior angles: they are on the outside of the parallel lines and opposite sides of the transversal. This means that they are congruent. So, we can set up an equation.
6x-2=4x+48
We subtract 4x from both sides.
2x-2=48
We add 2 to both sides.
2x=50
Divide both sides by 2.
x=25.
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Answer:
x = 25
∠A = 148
Step-by-step explanation:
opposite exterior angle ∠A = ∠B
where
∠A = 6x - 2°
∠B = 4x + 48°
6x - 2° = 4x + 48°
6x - 4x = 48° + 2°
2x = 50°
x = 50°/2
x = 25
plugin x into ∠A = 6x - 2°
∠A = 6(25) - 2°
∠A = 148