Answer:
Axis of symmetry: x = 2
Vertex at: (2, -13)
y-intercept is (0, -5)
Step-by-step explanation:
The equation for the x-value of the vertex in a quadratic of the form:
[tex]y=ax^2+bx+c[/tex]
is given by:
[tex]x_{vert}=-\frac{b}{2\,a}[/tex]
which in our case gives:
[tex]x_{vert}=\frac{8}{2*2} =2[/tex]
Then the equation for the axis of symmetry is given by: x = 2
and the y of the vertex can be calculated as:
[tex]y_{vert}=2 (2)^2-8\,(2)-5=-13[/tex]
Then the vertex is at the point: (2, -13)
And the y-intercept is found when x=0, that is:
y-intercept is (0, -5)
