A cylindrical tank of methanol has a mass of 60 kg and a volume of 75 L. Determine the methanol’s weight, den-sity, and specific gravity. Take the gravitational acceleration to be 9.81 m/s2. Also, estimate how much force is needed to accelerate this tank linearly at 0.25 m/s2.

Respuesta :

Answer:

Weight = 588.6 N

Density = 800 kg/m³

Specific Gravity = 0.8

Force = 147.15

Explanation:

W = mg

W = 60 * 9.81

W = 588.6 N

Volume from L to m³ would be

75 L = 75 * 1/1000

75 L = 0.075 m³

Recall, density = mass/volume, so then, density of methanol is.

Density = 60/0.075

Density = 800 kg/m³

Specific gravity, SG is equal to

SG = density of methanol/density of water

SG = 800/1000

SG = 0.8

the force needed to accelerate the tank, F = ma

F = 588.6 * 0.25

F = 147.15 N

Therefore, the needed variables are

Weight = 588.6 N

Density = 800 kg/m³

Specific Gravity = 0.8

Force = 147.15