Consider these shapes.
Shape A

3x^2+ 2
7x2 + 4x + 8
Shape B
3x^2+ 2

If shape B is a square, which polynomial represents the difference of the areas of shape A and shape B?
A. 8x +8x + 12
B. 12x^4+ 12x^3 + 26x^2 + 8x + 12
C. 32x^2 + 8x + 28
D. 30x^4 + 12x^3 + 40x^2 + 8x + 20

Consider these shapes Shape A 3x2 2 7x2 4x 8 Shape B 3x2 2 If shape B is a square which polynomial represents the difference of the areas of shape A and shape B class=

Respuesta :

Answer:

The correct answer is B :)

Step-by-step explanation:

The difference in the area of shape A and shape B is option B which is [tex]12x^{4}+12x^{3}+26x^{2} +8x+12[/tex].

What is area of rectangle and square?

Area of rectangle and square is the extent of surface rectangle and square exhibits into them. The area of rectangle is length * breadth and the area of square is side*side.

How to find area?

We have been given the length of shape A=[tex]7x^{2} +4x+8[/tex] and breadth be [tex]3x^{2} +2[/tex] and the side of shape B be [tex]3x^{2} +2[/tex].

Shape A looks like rectangle and shape B looks like square.

So the area becomes:

Area of shape A =[tex](3x^{2} +2) ( 7x^{2} +4x+8)[/tex]

we have to multiply both expressions

=[tex]21x^{4} +12x^{3} +24x^{2} +14x^{2} +8x+16[/tex]

=[tex]21x^{4} +12x^{3} +38x^{2}+8x+16[/tex]

Area of shape B=[tex](3x^{2} +2)(3x^{2} +2)[/tex]

=[tex]9x^{4} +6x^{2} +6x^{2} +4[/tex]

=[tex]9x^{4} +12x^{2} +4[/tex]

Difference=[tex]21x^{4}+12x^{3}+38x^{2} +8x+16-9x^{4} -12x^{2} -4[/tex]

=[tex]12x^{4} +12x^{3}+26x^{2} +8x+12[/tex]

Hence the difference between shape A and shape B is [tex]12x^{4} +12x^{3}+26x^{2} +8x+12[/tex].

Learn more about area at https://brainly.com/question/25965491

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