3. Five kissing cousins met at a family reunion.

Each cousin kissed each of the other cousins

just once. How many kisses were given in all?

Respuesta :

Answer: 20 kisses

Step-by-step explanation:

given data:

number of cousins at the family reunion = 5

each cousing kissing each other just once.

if one cousin kisses everybody round that would be

= 1 * 4

= 4 kisses.

4 kisses from each cousins * number of cousins at the family reunion.

= 4 * 5

= 20 kisses.

in total there were 20 kisses at family reunion

fichoh

Using the principle of combination, the number of kisses given in all by the five cousins is 10

  • Number of cousins, n = 5

Using the relation :

  • [n(n-1)] ÷ 2

Substituting the values into the relation :

[n(n-1)] ÷ 2

[5(5-1)] ÷ 2

(5 × 4) ÷ 2

20 ÷ 2

= 10 kisses

Hence, the Number of kisses exchanged in all is 10.

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