Answer:
The answer is "83.98, 1889.195, and 1889.195"
Explanation:
Given value:
[tex]\bold{P_{4}=2.34 \ kPa}[/tex]
In point a:
The value of [tex]h_{f4}=83.915 \ \ \frac{Kj}{kg}\\[/tex]
[tex]V_4=0.001002 \ \ \frac{Kj}{kg}\\\\U_4= 83.98 \ \ \frac{Kj}{kg}\\\\[/tex]
In point b:
calculating heat leaves formula= [tex]h_3-h_{f4}[/tex]
[tex]= 1973.11-83.915\\\\= 1889.195 \ \ \frac{KJ}{kg}[/tex]
In point c:
calculating Heat transfer rate formula[tex]=m(h_3-h_4)[/tex]
[tex]= 1(1889.195)\\\\ = 1889.19 \ \ kw.[/tex]