A compound is found to contain 46.68 % nitrogen and 53.32 % oxygen by mass. To answer the question, enter the elements in the order presented above. QUESTION 1: The empirical formula for this compound is . QUESTION 2: The molar mass for this compound is 30.01 g/mol. The molecular formula for this compound is

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dsdrajlin dsdrajlin · Answer 1 · 2020-09-11T02:18:25+02:00

Answer:

Q1: NO

Q2: NO

Explanation:

Step 1: Given data

Percentage by mass of nitrogen: 46.68%

Percentage by mass of oxygen: 53.32%

Step 2: Divide each percentage by the mass of the element

N: 46.68/14.01 = 3.332

O: 53.32/16.00 = 3.332

Step 3: Divide both numbers by the smallest one (in this case is the same)

N: 3.332/3.332 = 1

O: 3.332/3.332 = 1

The empirical formula is NO. Its molar mass is 30.01 g/mol.

Step 4: Calculate "n"

n = molar mass of the molecular formula / molar mass of the empirical formula

n = (30.01 g/mol) / (30.01 g/mol) = 1

Step 5: Determine the molecular formula

We do so by multiplying the empirical formula by "n".

NO × 1 = NO