The square root of a number is greater than the square of the number. For what set of numbers is this true? (0, 1) [0, 1] [1, ꝏ) (1, ꝏ)

Respuesta :

Answer:

(0,1)

Step-by-step explanation:

If you plug in    f(x)=[tex]\sqrt{x}[/tex]     and     g(x)=[tex]x^{2}[/tex]     into the calculator, you will find that from 0 to 1 that f(x) is rises above g(x). The parentheses are not [ ] because the question is not asking for greater than or equal to.

Answer:

(0,1)

Step-by-step explanation: