Given :
Mass of sample of camphor [tex](C_{10}H_{16}O)[/tex] , m = 130 g .
To Find :
the number of carbon atoms in given sample .
Solution :
Molecular mass of camphor is :
[tex]M=152\ g/mol[/tex] .
Moles of camphor ,
[tex]n=\dfrac{m}{M }\\\\n=\dfrac{130}{152}\\\\n=0.86[/tex]
1 mole of camphor contains 10 moles of carbon .
So , 0.86 moles of camphor contains 8.6 moles of carbon .
1 mole of any substance contains [tex]6.022 \times10^{23}[/tex] numbers of atoms/molecules .
So , number of atoms in 8.6 moles of carbon is :
[tex]N=6.022\times 10^{23}\times 8.6\\\\N=5.179\times 10^{24}[/tex]
Hence , this is the required solution .
