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The following table shows worldwide sales of a certain type of cell phone and their average selling prices in 2012 and 2013.
Year
2012
2013
Selling Price ($)
395
335
Sales (millions)
672
1,020
(a) Use the data to obtain a linear demand function for this type of cell phone. (Let p be the price, and let q be the demand).
(P) -
Use your demand equation to predict sales if the price is lowered to $245.
million phones
(b) Fill in the blank.
For every $1 increase in price, sales of this type of cell phone decrease by
million units.

Respuesta :

Answer:

(a) The linear demand function is q = 2962 - 5.80p; and sales is expected to be 1,488.80 millions if the price is reduced to $245.

(b) For every $1 increase in price, that sales of this type of cell phone decrease by 5.80 million units.

Step-by-step explanation:

(a) Use the data to obtain a linear demand function for this type of cell phone. (Let p be the price, and let q be the demand).

The form of the linear demand function we are trying to find will as follows:

q = a + bp ........................ (1)

Where;

q = sales = demand

a  = constant

b = slope

p = price

From the question, we have the following points:

Point 1 = (price in 2012, demand in 2012) = (p1, q1) = (395, 672)

Point 2 = (price in 2013, demand in 2013) = (p2, q2) = (335, 1020)

We can therefore calculate b as follows:

b = (q2 - q1) / (p2 - p1)

b = (1020 - 672) / (335 - 395)

b = 348 / (-60)

b = -5.80

Substituting for b in equation (1), we have:

q = a - 5.80p ..................... (2)

We can now use any of point 1 or 2 above to find a. Using point 1, we substitute p = 395 and q = 672 into equation (2) as follows:

672 = a - (5.80 * 395)

672 = a - 2291

a = 672 + 2291

a = 2963

Substituting the value for a back into equation (2) gives the demand function as follows:

q = 2962 - 5.80p <-------------- Linear demand function.

if the price is lowered to $245, we substitute p = 245 into the linear demand function as follows:

q = 2962 - 5.80(254)

q = 2962 -  1,473.20

q = 1,488.80

Therefore, sales is expected to be 1,488.80 millions if the price is reduced to $245.

(b) Fill in the blank. For every $1 increase in price, sales of this type of cell phone decrease by ______ million units.

From part (a), b is the slope and it -5.80 in the linear demand function. The slope shows how much q will change when p changes by $1.

Since the sales is in millions and slope is -5.80, it therefore implies for every $1 increase in price, that sales of this type of cell phone decrease by 5.80 million units.

The demand table is an illustration of a linear function

  • The demand linear equation [tex]\mathbf{q = -5.8p + 2963}[/tex]
  • The quantity demanded when the price is lowered to $245 is 1542 million
  • For every $1 increase in price, sales of this type of cell phone decrease by  5.8 million units.

(a) The linear demand function

From the table we have the following points

(p,q) = {(395,672) (335,1020)}

The demand linear equation is calculated using the following:

[tex]\mathbf{\frac{q - q_1}{p - p_1} = \frac{q_2 - q_1}{p_2 - p_1}}[/tex]

So, we have:

[tex]\mathbf{\frac{q - 672}{p - 395} = \frac{1020- 672}{335- 395}}[/tex]

[tex]\mathbf{\frac{q - 672}{p - 395} = -\frac{348}{60}}[/tex]

[tex]\mathbf{\frac{q - 672}{p - 395} = -5.8}[/tex]

Cross multiply

[tex]\mathbf{q - 672 = -5.8(p - 395)}[/tex]

[tex]\mathbf{q - 672 = -5.8p + 2291}[/tex]

Add 672 to both sides

[tex]\mathbf{q = -5.8p + 2963}[/tex]

(b) The quantity when the price is $245

This means that p = 245.

So, we have:

[tex]\mathbf{q = -5.8\times 245 + 2963}[/tex]

[tex]\mathbf{q = -1421 + 2963}[/tex]

[tex]\mathbf{q = 1542}[/tex]

Hence, the quantity demanded when the price is lowered to $245 is 1542 million

(c) Interpret the demand equation

For every $1 increase in price, sales of this type of cell phone decrease by  5.8 million units.

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