Answer:
x + 3 + [tex]\frac{13}{x-3}[/tex]
Step-by-step explanation:
Using long division
x + 3 ← quotient
--------------------------
x - 3 | x² + 0x + 4
x² - 3x ↓
------------------------
3x + 4
3x - 9
-----------------------
13 ← remainder
Thus
[tex]\frac{x^2+4}{x-3}[/tex] = x + 3 + [tex]\frac{13}{x-3}[/tex]