The horizontal displacement of the projectile is 25.98 m.
The given parameters;
angle of projection Ф = 30°
initial velocity of the projectile, u = 15 m/s
time of motion, t = 2 seconds
The horizontal displacement of the projectile is calculated as follows;
[tex]X = v_0_x \times t\\\\X = v_0 cos (\theta) \times t\\\\X = 15\times cos (30) \times 2\\\\X = 25.98 \ m[/tex]
Thus, the horizontal displacement of the projectile is 25.98 m.
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