Can someone help me solve this fast??

Answer:
[tex]x=7[/tex]
Step-by-step explanation:
[tex]\sqrt{3x+8}=\sqrt{4x+1}[/tex]
Square both sides:
[tex](\sqrt{3x+8})^{2} =(\sqrt{4x+1})^{2}[/tex]
[tex]3x+8=4x+1[/tex]
Subtract 8 from both sides:
[tex]3x+8-8=4x+1-8[/tex]
[tex]3x=4x-7[/tex]
Subtract 4x from both sides:
[tex]3x-4x=4x-7-4x[/tex]
[tex]-x=-7[/tex]
Divide both sides by -1:
[tex]\frac{-x}{-1}=\frac{-7}{-1}[/tex]
[tex]x=7[/tex]